Question 1166355
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The maximum number of shelves that could be required is 5: 240 cm divided by 48 cm (the width of three 16 cm wide books, the most that could fit on one shelf) given that all of the books measured 16 cm.


But even in the optimum case where the assortment of thicknesses was such that it was possible to fill four shelves completely, 240 divided by 56 is 4 with a remainder, so you would have to put 16 centimeters worth of books on the fifth shelf, so the minimum number is also 5.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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I > Ø
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