<PRE><B>Question 1166377</B>
&lt;br&gt;
The opposite of &quot;at least one card is a club&quot; is &quot;no cards are clubs&quot;.  So the probability that at least one is a club is 1 minus the probability that none are clubs.&lt;br&gt;
The probability that the first card drawn is not a club is 39/52;
the probability that the second is not a club is 38/51;
...&lt;br&gt;
The probability that none of the five cards drawn is a club is&lt;br&gt;
{{{(39/52)(38/51)(37/50)(36/49)(35/48)}}}&lt;br&gt;
And then the probability that at least one is a club is 1 minus that number.&lt;br&gt;
Use a calculator if you need to get a simplified answer.&lt;br&gt;
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