Question 108407
The answer is going to be , no solution. When it is worked out, you cancel both variables.
You are close;
4x-12y=5
-x+3y=-1
=================
-x=-1-3y
x=1+3y
================
4(1+3y)-12y=5
4+12y-12y=5
{{{4+cross(12y)-cross(12y)=5}}}
4=5
no solution
:)