Question 1166283
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The given numbers are...
3 = 3(1^2)
12 = 3(2^2)
27 = 3(3^2)
48 = 3(4^2)<br>
So the n-th term is <b><i><u>PROBABLY</u></i></b> 3(n^2).<br>
However, the problem as stated is invalid, because ANY following numbers would make a valid sequence.<br>