Question 1166088
Strikes the ground when h(t)=0
this means 144-16t^2=0
16t^2=144
t^2=9
t=3 seconds

average velocity during that time is (144-0)/(3-0)=48 mph={f(a)-f(b)/b-a)}

v=(1/2)(a(t+h)^2)-(1/2)at^2 divided by h
=(1/2) a (t^2+2th+h^2)-at^2 or 1/2 {at^2+2th+h^2-at^2) divided by h
=(1/2) a (*2th+h^2) divided by h
=(1/2)(2at+ah)
=at+(ah/2)
when h goes to 0 the instantaneous velocity is= at
so at 1 second it is 32 ft/second (32 ft/sec^2*1 sec)
at 2 seconds it is 64 ft/sec
general it is 32 t seconds.

when it strikes the ground v=sqrt(2ax)=sqrt(2*32*144)=96 ft/sec