Question 1166083
I'm assuming log here means log base 10
Using the rule log(a) - log(b) = log(a/b) we have:
log((10+9x)/(11-x)) = 2
To eliminate the logarithm, we use the exponential form:
10^(log((10+9x)/(11-x))) = 10^2
(10+9x)/(11-x) = 100
Solving for x gives 1100 - 100x = 10 + 9x -> 109x = 1090 -> x = 10
Check: log(10+90) - log(1) = 2