Question 1165802
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<pre>

You are given  {{{sin(theta)}}} = {{{6/sqrt(61)}}}.


Then  {{{cos(theta)}}} = +/- {{{sqrt(1-sin^2(theta))}}} = +/- {{{sqrt(1-36/61)}}} = +/- {{{sqrt((61-36)/61))}}} = +/- {{{sqrt(25/61)}}} = +/- {{{5/sqrt(61)}}}.


Since  {{{theta}}}  is in QII, the sign of the cosine is  " - ",  so the answer is  - {{{5/sqrt(61)}}}.


Use your calculator.
</pre>

Solved.