Question 1165797
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cos(sin^-1 12/13) = {{{sqrt(1-(12/13)^2)}}} = {{{sqrt(1 - 144/169)}}} = {{{sqrt(25/169)}}} = {{{5/13}}}.    



Therefore,  sec(sin^-1(12/13)) = {{{1/cos(sin^-1(12/13))}}} = {{{13/5}}}.   <U>ANSWER</U>
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