Question 108378
Is this what you mean?
{{{1/(4(x+1)^2)-16=0}}}
{{{1/(4(x+1)^2)=16}}}
{{{1/4=16(x+1)^2}}}
{{{1/64=(x+1)^2}}}
{{{sqrt(1/64)=sqrt((x+1)^2)}}}
{{{(x+1)=1/8}}} and {{{(x+1)=-1/8}}}
{{{x+1=1/8}}}
{{{highlight(x=-7/8)}}}
{{{x+1=-1/8}}}
{{{highlight(x=-9/8)}}}