Question 1165754
perpendicular lines have slope products=-1
so the line needed has a slope of +(1/5)
use point slope where y-y1=m((x-x1), m slope and (x1, y1) point
y-3=(1/5)(x+30)
y=(1/5)x+9 ANSWER

{{{graph(300,300,-20,20,-20,20,-5x+86,0.2x+9)}}}