Question 1165411
Jones scale: Freezing point = 40, Boiling point = 280
Smith scale: Freezing point = 25, Boiling point = 125
We need to find a relationship between the two scales
On the Jones scale, the difference between boiling and freezing is 280 - 40 = 240
On the Smith scale, the difference between boiling and freezing is 125 - 25 = 100
Thus, the Jones scale has 240/100 = 2.4 degrees for every 1 degree on the Smith scale
J = 2.4S + T0, where T0 is the yet to be determined intercept
Use one of the given points to determine T0
40 = 2.4*25 + T0 -> T0 = -20
So J = 2.4S - 20
97 = 2.4S - 20
S = 117/2.4 = 48.8 deg.