Question 1165352
Two fire towers are 30 km apart.
 A fire is spotted from the distant West tower at 18° N of E while the same fire is spotted from the East tower at 41° N of W.
 How much closer is the East Tower to the fire than the West tower?
:
this forms a simple triangle ABC where AB is the base of 30 km,
A is the west tower with an angle of 18
B is the east tower with an angle of 41
:
a = east tower dist to fire
b = west tower dist to fire
:
Find the 3rd angle which is at the fire
180 - 18 - 41 = 121 degrees
:
Use the law of sines
{{{a/sin(18)}}} = {{{30/sin(121)}}}
Cross multiply
sin(121)a = 30*sin(18)
then 
a = {{{(30*sin(18))/sin(121)}}}
a = 10.82 mi east tower to fire
and
{{{b/sin(41)}}} = {{{30/sin(121)}}}
Cross multiply
sin(121)a = 30*sin(41)
then 
b = {{{(30*sin(41))/sin(121)}}}
b = 22.96 mi west tower to fire
:
" How much closer is the East Tower to the fire than the West tower?"
22.96 - 10.82 = 12.14 mi is the east tower closer than the west tower