Question 1165458
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<pre>

(a)  (1-0.25)*(1-0.20)*(1-0.05) = 0.75*0.7*0.95 = 0.49875 = 1 - 0.50125.

     An equivalent single discount is 50.125%.



(b)  Two consecutive discounts of 30% and 20%  make the equivalent discount 

         (1-0.3)*(1-0.2) = 0.7*0.8 = 0.56 = 1 - 0.44

      of 44%.


     So, three consecutive discounts of (a) are "better" than two consecutive discounts of (b).
</pre>

Solved and explained.


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&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/percentage/lessons/Percentage-problems-on-chains-of-discounts.lesson>Percentage problems on chains of discounts</A> 

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