Question 1165410

Can someone help me solve this question by using completing the square method?

4.6y^2 + 3.5x - 1.75 = 0

I have tried everything but still cant solve it. thanks.
<pre>It's easier to work with integers than decimals. Therefore, let's convert all the decimal-coefficients by multiplying entire equation by 20.
{{{matrix(1,3, 20(4.6y^2 + 3.5x - 1.75), "=", 20(0))}}}
{{{matrix(1,3, 92x^2 + 70x - 35, "=", 0)}}}
{{{matrix(1,3, 92x^2/92 + (70/92)x - 35/92, "=", 0/92)}}} ------- Dividing entire equation by 92 in order to get a leading coefficient of + 1
{{{matrix(1,3, x^2 + (70/92)x - 35/92, "=", 0)}}} 
{{{matrix(1,3, x^2 + (70/92)x, "=", 35/92)}}} ------- Adding {{{35/92}}} to get the constant on the right-side
{{{matrix(1,3, x^2 + (70/92)x + ((1/2) * (70/92))^2, "=", 35/92 + ((1/2) * (70/92))^2)}}} ------- Taking {{{1/2}}} the value of "b," squaring it, and then adding the result to both sides
{{{matrix(1,3, x^2 + (70/92)x + (35/92)^2, "=", 35/92 + (35/92)^2)}}}
{{{matrix(1,3, (x + 35/92)^2, "=", 35/92 + (35/92)^2)}}}
{{{matrix(1,3, sqrt((x + 35/92)^2), "=", ""+- sqrt(35/92 + (35/92)^2))}}} ------- Taking square root of both sides
{{{matrix(1,3, x + 35/92, "=", ""+- sqrt(35/92 + (35/92)^2))}}}
{{{matrix(1,3, x, "=", ""+- sqrt(35/92 + (35/92)^2) - (35/92))}}}
{{{highlight_green(system(matrix(1,8, x, "=", sqrt(35/92 + (35/92)^2) - (35/92), ",", or, x, "=", - sqrt(35/92 + (35/92)^2) - (35/92)), matrix(1,8, x, "=", highlight(0.344248187), ",", or, x, "=", highlight(- 1.105117752))))}}}