Question 1165370
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If a formal algebraic solution is not required, here is a quick and easy way to solve any 2-part mixture problem like this.<br>
(1) Find where the per-packet price for the mixture lies between the per-packet prices of the two types of seeds.<br>
4.56-2.32 = 2.24
2.88-2.32 = 0.56
0.56/2.24 = 1/4<br>
The per-packet price for the mixture is one-fourth of the way from $2.24 to $4.56.<br>
(2) That means 1/4 of the packets in the assortment are packets of the higher-priced seed.<br>
ANSWER: 1/4 of 16 packets, or 4 packets, of the hot-pepper seeds; the other 12 packets are of sweet-pepper seeds.<br>
CHECK:
12(2.32)+4(4.56) = 27.84+18.24 = 46.08
16(2.88) = 46.08<br>