Question 1165303
Given the function f(x)=x<sup>2</sup>+2x+1, find:
a) f(−7)
<pre>
Start with 

f(x) = x<sup>2</sup> + 2x + 1

1. Take out all the x's, and replace them with open parentheses

f(  )= (  )<sup>2</sup> + 2(  ) + 1

2. Put -7's in the parentheses:

f(-7)= (-7)<sup>2</sup> + 2(-7) + 1

Leave the left side as it is and simplify the right side:

f(-7)= 49 - 14 + 1

f(-7)= 36

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</pre> 
b) f(0)
<pre>
Start with 

f(x) = x<sup>2</sup> + 2x + 1

1. Take out all the x's, and replace them with open parentheses

f( )= ( )<sup>2</sup> + 2( ) + 1

2. Put 0's in the parentheses:

f(0)= (0)<sup>2</sup> + 2(0) + 1

Leave the left side as it is and simplify the right side:

f(0)= 0 + 0 + 1

f(0)= 1

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</pre>
c). f( 1/4 )
<pre>
Start with 

f(x) = x<sup>2</sup> + 2x + 1

1. Take out all the x's, and replace them with open parentheses

f(   ) = (  )<sup>2</sup> + 2(  ) + 1

2. Put 1/4's in the parentheses:

f(1/4) = (1/4)<sup>2</sup> + 2(1/4) + 1

Leave the left side as it is and simplify the right side:

f(1/4) = 1/16 + 1/2 + 1

f(1/4) = 1/16 + 8/16 + 16/16

f(1/4) = 25/16

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</pre>
d) f(0.3)
<pre>
Start with 

f(x) = x<sup>2</sup> + 2x + 1

1. Take out all the x's, and replace them with open parentheses

f(  )= (  )<sup>2</sup> + 2(  ) + 1

2. Put 0.3's in the parentheses:

f(0.3)= (0.3)<sup>2</sup> + 2(0.3) + 1

Leave the left side as it is and simplify the right side:

f(0.3)= 0.09 + 0.6 + 1

f(0.3)= 1.69

Edwin</pre>