Question 1165213
a. SEM is 36000/sqrt(78)=$4076.20
b. A sample from a normal distribution may be considered normal as well. The curve is narrower and steeper, as the variance is much less than for an individual.
c.the z would be 5000/4076.20 or 1.23.  That would be 0.1093
d. c would also be the answer for < 131000, so the answer to d is 0.8997, the complement
e. Here, the z value is between -1.23 and +1.23, and that probability is 0.7813