Question 1164992
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Use the Two-Point Form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \frac{y_2\,-\,y_1}{x_2\,-\,x_1}\(x\ -\ x_1}]


You have already calculated *[tex \Large \frac{y_2\,-\,y_1}{x_2\,-\,x_1}] which is the slope, so you could use the Point-Slope Form:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1)]


Either way, what you get is an equation of the desired line.  You can also put it into Slope-intercept form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\  mx\ +\ b]


Where *[tex \Large b\ =\ mx_1\ + y_1]


Or Standard form by writing the slope as a fraction *[tex \Large \frac{-A}{B}] and *[tex \Large C\ =\ Bb] and then the form is


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Ax\ +\ By\ =\ C]

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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