Question 108243
the given equation is:


3x - 6y = 9 


Writing this equation in the slope intercept form, we get: 



{{{y = (x/2) - (3/2)}}} 


therefore the slope in the above equation is m = (1/2) 


We know that 2 lines are perpendicular when the product of their slopes are equal to -1.


So the slope of the second line is = -2 


Now substituing the point and the slope in the one point form we get the required line.


(y - y1) = m(x - x1) 


(y - (-1)) = (-2)(x - (-2)) 


y + 1 = (-2)( x + 2)


y + 1 = -2x - 4


==> y = -2x - 5


thus the required line