Question 1164947
The distance travelled to retrieve each potato will be twice the distance from the starting point to the potato. 
The first distance will be 12 m since the first potato is located 6 m from the starting point
In general, the distance travelled to retrieve the n-th potato is represented by an arithmetic sequence, 
with the first term equal to 12.  The common difference is 10, twice the distance between each potato.
Thus a_n = 12 + 10(n-1)
The sum of 10 terms of the arithmetic sequence S_n = (10/2)*(12 + 102) = 570 m