Question 1164936
<pre>
               SPEED        TIME        DISTANCE

x             30/(t+3)      t+3          30

y             30/t          t            30

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x           60/(t+3)     (t+3)/2        30

y           30/t          t             30

difference              (3/2)
</pre>
{{{t-(t+3)/2=3/2}}}

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Solving that equation gives {{{highlight_green(t=6)}}}


Speed for x,  {{{30/(6+3)=30/9=10/3=highlight(3&1/3)}}}{{{k/hour}}}
Speed for y, {{{highlight(5)}}}{{{k/hour}}}



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A different opinion or approach may be good.