Question 1164920
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&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<U>Solution 1</U>


<pre>
Let d be the distance between the cities A and B.


Terence' traveled time was 4 hours (from noon till 4pm).

Hence, Terence' average speed was  {{{d/4}}}  hours.


It means that the Linda's average speed was  {{{d/4 - 15}}} km/h  (15 km/h slower than that of Terence).


In 4 hours, from noon till 4 pm, Linda covered 224 kilometers.

It gives you this equation

    {{{4*(d/4- 15)}}} = 224,  or

    {{{d/4- 15}}} = {{{224/4}}} = 56.


Multiply both sides by 4 to get

    d - 60 = 56*4 = 224

    d = 224 + 60 = 284.


<U>ANSWER</U>.  The distance between the cities is 284 km.
</pre>

Solved.



&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<U>Solution 2</U>


<pre>
Another way to solve this problem is to write so called  "speed equation"

    {{{d/4}}} - {{{224/4}}} = 15


Saying that the difference between two speeds,  {{{d/4}}}  and  {{{224/4}}} is 15 km/h.


Then from the equation you get

    {{{d/4}}} - 56 = 15,

    {{{d/4}}} = 15 + 56 = 71,

    d = 4*71 = 284,


giving the same answer.
</pre>


&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<U>Solution 3</U>


In this way, &nbsp;you even may solve the problem &nbsp;MENTALLY, &nbsp;without using equations.


<pre>
The average speed of Linda is  {{{224/4}}} = 56 km/h.


The average speed of Terence is 15 km/h faster, i.e.  56+15 = 71 km/h.


Then the distance from A to B, which Terence covers in 4 hours, is  71*4 = 284 kilometers.
</pre>


It is the same solution as in &nbsp;Version #2 in this post, &nbsp;simply presented in wording form.