Question 108234
{{{(2x-3)^2=-25}}}
{{{sqrt((2x-3)^2)=sqrt(-25)}}}
{{{2x-3=sqrt(-25)}}}


{{{sqrt(-25)}}} is NOT a real number!   So

Let {{{i}}}={{{sqrt(-1)}}}


Thus,

{{{2x-3=sqrt(-25)}}}
{{{2x-3=sqrt((-1)*25))}}}
{{{2x-3=sqrt(25) sqrt(-1)}}}
{{{2x-3=0 +- 5i}}}
{{{2x=3+- 5i}}}
{{{x=(3+5i)/(2)}}}


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