Question 1164841
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*[tex \Large gh] means *[tex \Large g] times *[tex \Large h], so *[tex \Large (gh)(n)\ =\ (n^2\,+\,2n)(-3n\,+\,2)]


You didn't say, but that probably has to be expanded and like terms collected.  That part is on you.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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