Question 1164802
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A bank loaned out $7,500, part of it at the rate of 14% annual interest, and the rest at 9% annual interest. 
The total interest earned for both loans was $825.00. How much was loaned at each rate?
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Let x be the amount loaned at 14% annual interest.

Then the amount loaned at 9% interest is  (7500-x) dollars.


The total interest equation is


    0.14x + 0.09*(7500-x) = 825  dollars.


From the equation,


    x = {{{(825 - 0.09*7500)/(0.14-0.09)}}} = 3000.


<U>ANSWER</U>.  $3000 was loaned at 14%  and  the rest, 7500-3000 = 4500 dollars was loaned at 9%.


<U>CHECK</U>.  0.14*3000 + 0.09*4500 = 825  dollars.   ! Correct !
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Solved.