Question 1164786
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This linear equation has no constant term.  That means you can't find x- and y-intercepts by setting y=0 and x=0.<br>
Since you can't find x- and y-intercepts, you need to use a different method for making the graph.<br>
Another easy way to make a graph of a linear equation is using slope-intercept form, y = mx+b.  In that form, the y-intercept is (0,b) and the slope is m.<br>
{{{3y = -5x}}}<br>
Divide by 3 to get the equation in y=mx+b form.<br>
{{{y = (-5/3)x}}}
or
{{{y = (-5/3)x+0}}}<br>
So the y-intercept (and x-intercept) is (0,0), and the slope is -5/3.<br>
So your first point can be (0,0).  Then use the slope to find the second point.  Slope = rise/run = -5/3, so, starting at (0,0), move 5 down (a rise of -5) and 3 to the right (a run of 3).  Your second point is (3,-5).<br>