Question 1164780
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Calculate *[tex \Large 3^5], then calculate *[tex \Large 3^4].  Then calculate *[tex \Large 3^5\ -\ 3^4].  Set *[tex \Large 2a^b\ =\ 3^5\ -\ 3^4].  Divide both sides by 2.  The answer should be obvious by that time.  Hint:  Look at a table of perfect squares.


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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