Question 1164712
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Let *[tex \Large x] represent the number produced by B.  Then *[tex \Large 3x] is the number produced by A, and *[tex \Large 3x\ +\ 13] is the number produced by C.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ x\ +\ (3x\ +\ 13)\ =\ 4997]


Solve for *[tex \Large x], then calculate *[tex \Large 3x] and *[tex \Large 3x\ +\ 13]

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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