Question 251591
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It's obvious from the work you show that you have....
F = Faith's age
E = Ed's age
F-8 = Faith's age 8 years ago
E-8 = Ed's age 8 years ago
F+6 = Faith's age 6 years from now
E+6 = Ed's age 6 years from now<br>
The work you have done there -- coming up with the expressions representing their ages 8 years ago and 6 years from now -- was exactly right.  So you have an excellent start on solving the problem.<br>
So let's look at why your equations didn't get you to the solution to the problem.<br> 
Let's re-phrase the given information using the language of equations.  Then we will look at how to use the expressions you have to write those equations, and we will compare that to the equations you wrote.<br>
(1) Ten times Faith's age eight years ago was equal to Ed's age eight years ago.<br>
Ed's age 8 years ago was E-8; Faith's age 8 years ago was F-8.  10 times Faith's age 8 years ago is then 10(F-8).  So the equation should be<br>
10(F-8) = E-8<br>
Your equation was<br>
10F-8 = E-8<br>
Do you see that the expression on the left side of your equation does NOT say "10 times Faith's age 8 years ago"?<br>
So your mistake was the simple one of not using parentheses where required to make the equation say what you meant it to say.<br>
So, with the good start you had, I think that, with just a little more care to make sure your equations say what you mean for them to say, you will do okay with solving these kinds of problems.<br>
(2) Three times Faith's age six years from now will be Ed's age six years from now.<br>
I hope you see that your mistake here is exactly the same thing.  The left side of your second equation does NOT represent "3 times Faith's age 6 years from now".  That left side of that equation has to be 3(F+6) -- not just "3F+6".<br>