<PRE><B>Question 108296</B>
At 10:00 A.M. a  car leaves a house at a rate of 60mi/h. At the same time another car leaves the same house at a rate of 50mi/h in the opposite direction. At what time will the cars be 330 miles apart?
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1st car DATA:
rate = 60 mph ; time = x hrs ; distance = rt = 60x miles
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2nd car DATA:
rate = 50 mph ; time = x hrs ; distance = rt = 50x miles
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EQUATION:
distance + distance = 330 miles
60x + 50x = 330 
110x = 330
x = 3 hrs
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10:00 AM + 3 hrs = 1:PM
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Cheers,
Stan H.</PRE>