Question 1164551
<font face="Times New Roman" size="+2">

Polynomial equations of degree *[tex \Large n] have *[tex \Large n] solutions over the Complex numbers.  What is the degree of your equation?

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
</font>