Question 1164463
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No figure is shown; but the statement of the problem is sufficient to solve the problem.<br>
The perimeter of the field is twice one dimension plus twice the other.  When the field is divided into two parts, presumably the total amount of fencing is three times one dimension plus two times the other.  So<br>
{{{2x+2y=80}}}
{{{3x+2y=91}}}<br>
The difference between the two equations is<br>
{{{x=11}}}<br>
Then plugging x=11 in either of the original equations gives us y=9.<br>
ANSWER: The field is 9x11 meters.<br>