Question 1164402
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<pre>

You are given


    {{{f(sqrt(x+1))}}} = {{{1/x}}}.    (1)


You want to make the argument of the function f equal to 2.


In other words, you want to have


    {{{sqrt(x+1)}}} = 2.


It implies  (after squaring both sides) 

    x + 1 = 4,  and then  x = 4-1 = 3.


Indeed,  then  {{{sqrt(3+1)}}} = {{{sqrt(4)}}} = 2.


Very good.   Then at x= 3,  the right side of the equation (1) is  {{{1/x}}} = {{{1/3}}}.


<U>ANSWER</U>.  f(2) = {{{1/3}}}.
</pre>

Solved.


Is everything clear to you in my solution ?



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