Question 108198
subtracting the first equation from the third gives 5y-4z=10


subtracting 2 times the first equation from the second gives 9y+3z=18


(4/3)(9y+3z=18) ... 12y+4z=24 ... adding 5y-4z=10 gives 17y=34 ... y=2


x-(3)*(2)=0 ... x=6


6+2(2)-4z=10 ... -4z=0 ... z=0