Question 1164326
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ M\ =\ \(\frac{L}{F}\)\(\frac{25}{f}\,+\,1\)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{MF}{L}\,-\,1\ =\ \frac{25}{f}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{MF\,-\,L}{25L}\ =\ \frac{1}{f}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f\ =\ \frac{25L}{MF\,-\,L}]


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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