Question 1164209
Susan cashed a check at the bank, but the teller made a mistake.
 He gave her as many dollars as he should have given her cents and as many cents as he should have given her dollars.
 Susan took the money without realizing the error and spent $3.50.
 She then had twice as much money as the actual amount of the check.
 What was the amount of the check?
;

let c = correct no. of cents
let d = correct no. of dollars
then
(d+.01c) = amt of the check
and
(c+.01d) = amt paid by teller
:
c + .01d - 3.50 = 2(d+.01c)
c + .01d - 3.50 = 2d + .02c
c -.02c + .01d - 2d = 3.50. 
.98c - 1.99d = 3.50
Set up as an equation that we can graph on our calc and check the table
y=c; x=d
y = {{{(1.99x+3.50)/.98}}}
only one, two digit, integer solution
d = 14, c = 32
Actual check value: $14.32, teller paid $32.14
:
:
See if that checks out
$32.14
 -3.50
-------
$28.64 which is twice $14.32