Question 1164205
 Perform the indicated operation and express the results as a simplified complex number. (Express your answer in the form (a + bi).)
{{{(3+4i)/(2-5i)}}}
multiply the discriminant of the denominator over itself. i^2=-1
{{{(3+4i)/(2-5i)}}} * {{{(2+5i)/(2+5i)}}} = {{{((3+4i)(2+5i))/((2-5i)(2+5i))}}} = {{{(6+15i+8i+20i^2)/(4-25i^2)}}} = {{{(6+23i+20(-1))/(4-25(-1))}}} = {{{(6+23i-20)/(4+25)}}}
{{{(-14+23i)/29}}} = {{{-14/29}}}+{{{23/29}}}i