Question 1164151
<pre>
Instead of doing your problem, here is another one EXACTLY like yours
in every way for you to use as a model in doing yours:
</pre>
How to find the number?  The units digit of a two-digit number is five more
than the tens digit. The number is equal to three times the sum of the
digits. Find the number.(Hint:we can represent a two digit number as 10t+u.)
<pre>
t = tens digit
u = units digit
10t+u = the two-digit number
t+u = sum of digits
</pre>
The units digit of a two-digit number is five more than the tens digit. 
<pre>
units digit = tens digit + 5
      u     =     t      + 5

u = t + 5
</pre>
The number is equal to three times the sum of the digits. 
<pre>
The number = 3 times sum of digits
  10t+u    = 3   ∙     (t+u)

10t + u = 3(t + u)
</pre>
Find the number.
<pre>
Substitute t + 5 for u in

    10t + u = 3(t + u)

10t + t + 5 = 3(t + t + 5)

    11t + 5 = 3(2t + 5)

    11t + 5 = 6t + 15
     
         5t = 10

          t = 2

Substitute 2 for t in  

          u = t + 5
        
          u = 2 + 5

          u = 7

The tens (first) digit is 2 and the units (second) digit is 7.

So the number is 27.

Now do your problem the exact same way.

Edwin</pre>