Question 1164055
<br>
the number: n
twice the number: 2n
3 less than the number: n-3
the sum of (twice the number) and (3 less than the number): (2n)+(n-3)<br>
the difference between -19 and the number: -19-n<br>
So<br>
{{{(2n)+(n-3) = -19-n}}}<br>
Solve using basic algebra.<br>
A comment about the response from one of the other tutors....<br>
In everyday language, the difference between two numbers is nearly always interpreted as being a positive number.  So the difference between 5 and 10 is 5, and the difference between 10 and 5 is 5.<br>
However, in formal mathematics, the difference between A and B is ALWAYS A-B.  So the difference between 5 and 10 is 5-10 = -5, and the difference between 10 and 5 is 10-5 = 5.<br>
So in your problem "the difference between -19 and the number" is -19-n -- NOT n-(-19) = n+19.<br>