Question 1164045
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The future value, *[tex \Large A], of an investment of *[tex \Large P] at a rate of *[tex \Large r] percent per annum compounded *[tex \Large n] times per year for *[tex \Large t] years is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ P\(1\,+\,\frac{r}{100n}\)^{nt}]


You want the time for *[tex \Large P] to grow to *[tex \Large A], so


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \(1\,+\,\frac{r}{100n}\)^{nt}\ =\ \frac{A}{P}]


Plug in the numbers you know, namely *[tex \Large A], *[tex \Large P], *[tex \Large r], and *[tex \Large n], and then solve for the remaining variable, *[tex \Large t]


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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