Question 1164009
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One drove *[tex \Large d] miles at *[tex \Large 68\text{ mph}] in some amount to time, *[tex \Large t].  So:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ t\ =\ \frac{x}{68}]


The other drove *[tex \Large d\ -\ 120] miles at *[tex \Large 44\text{ mph}] in the same amount to time, *[tex \Large t].  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ t\ =\ \frac{x\,-\,120}{44}]


Since the time is the same:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x}{68}\ =\ \frac{x\,-\,120}{44}]


Solve for *[tex \Large x]

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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