Question 1163993
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Direct Proportion:  One value goes up, the other goes up (or Down and Down)


Inverse Proportion:  One value goes up, the other goes down (or Down and Up)


My first clue for this problem was "The number of Pokémon you see is inversely proportional..."  A good strategy for this kind of problem is to actually read the problem statement.  In fact that works almost every time.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  P\ =\ \frac{k}{D}]


Plug in the initial condition numbers you know, and then calculate the value of *[tex \Large k].  Once you know the constant of proportionality, you can calculate either value given the other one.


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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