Question 1163952
The first person's speed is s1 = d/2 (mi/h) where d is the total length of the road
The second person's speed is s2 = d/3 (mi/h)
The first person has walked a distance of d/2 + 4 4/5 when they meet
The second person has walked a distance of d/2 - 4 4/5 when they meet
Since they both walk for the same time, we can set the times equal to each other:
time = distance/speed
(d/2 + 4 4/5)/(d/2) = (d/2 - 4 4/5)/(d/3)
Solve for d: d + 48/5 = 3d/2 - 72/5
d/2 = 120/5 -> d = 48 mi