Question 1163944
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Let {{{t[s]}}} be the reading of the slower clock;  t be the normal clock reading (= actual time).


Then from the condition  {{{(t[s] - 8)/(t-8)}}} = {{{(60-4)/60}}} = {{{56/60}}} = {{{14/15}}}  for any time interval t after 8:00 am.


When this clock hits 12 at noon exactly, {{{t[s]-8}}} = 4;  hense


    {{{4/(t-8)}}} = {{{56/60}}},  or


    {{{4/((56/60))}}} = t - 8

    {{{(4*60)/56}}} = t-8

    {{{60/14}}} = t -8

    t-8 = 4 hours + {{{4/14}}} of an hour = 4 hours and 0.286 of an hour = 4 hours 17 minutes and 9.6 seconds.


<U>ANSWER</U>.  At this moment, the correct time is  17 minutes and 9.6 seconds after noon.
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Solved.