Question 1163877
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<pre>
Sum   Ways
2     1,1
3     1,2 2,1
4     1,3 2,2 1,3
5     1,4 2,3 3,2 4,1
6     2,4 3,3 4,2
7     3,4 4,3
8     4,4
</pre>

There are 16 possible combinations, 6 three ways, more than 6 three ways, and less than 6 ten ways.  So if X is the of points won:

<pre>
  X   P(X)    xP(x)
  3   0.375   1.05
  2   0.375   0.75
 -1   0.675  -0.675

    ∑xP(x) =  1.125
</pre>     


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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