Question 1163881
the sum of the exterior angles of a polygon is always 360.
you have 3 exterior angles of 50 degrees = 150 degrees.
each exterior angle of a polygon is supplemental to its corresponding interior angle.
you have one interior angle of 127 degrees subtracted from 180 degrees equals one exterior angle of 53 degrees
you have one interior angle of 135 degrees subtracted from 180 degrees equals one exterior angle of 45 degrees.
altogether, you have 5 exterior angles with a sum of 248 degrees.
since the sum of all the exterior angles must be equal to 360 degrees, you have 360 - 248 = 112 degrees missing.
since the remaining interior angles are 173 degrees each, then the remaining exterior angle has to be 180 - 173 = 7 degrees each.
therefore, 112 / 7 = 16 exterior angles missing.
the total number of exterior angles is therefore 5 plus 16 = 21, bringing the total number of exterior angles degrees equal to 248 plus 112 = 360.
the value of n therefore has to be 16 plus 5 = 21.


it doesn't matter how many sides the polygon has;  the sum of the exterior angles is always 360.