Question 1163881
Three of the exterior angles of an n-sided polygon are 50°each, two of its iterior angles are 127° and 135°,and the remaining interior angles are 173°each. Find the value of n. 
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Use all exterior angles:
Three of the exterior angles of an n-sided polygon are 50°each, two of its exterior angles are 53° and 45°,and the remaining exterior angles are 7°each. Find the value of n
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Add the given angles
3*50 + 53 + 45 + x*7 = 360
248 + x*7 = 360
7x = 112
x = 16 angles
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Add the # of angles ( = n, # of sides)
3 + 1 + 1 + 16 = 21 sides