Question 108148
{{{(6*10^12)(3.2*10^8)/ (1.6*10^7)(3*10^2)}}}

what we can cancel her is:


{{{6}}} and {{{3}}} divide both by {{{3}}}


{{{3.2}}} and {{{1.6}}} divde both by {{{1.6}}}


{{{10^12}}} and {{{10^7}}} both divide by {{{10^7}}};so, you will have

 
{{{10^12/10^7 = 10^(12-7) = 10^5}}}, and {{{10^7/10^7=1}}}


{{{10^8}}} and {{{10^2}}} both divide by {{{10^2}}};so, you will have 


{{{10^8/10^2 = 10^(8-2) = 10^6}}}, and {{{10^2/10^2=1}}}


then we have:


{{{(2*10^5)(2*10^6)}}}


{{{(4*10^(5+6))}}}


{{{(4*10^11)}}}