Question 1163850
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The *[tex \Large n]th odd integer is *[tex \Large 2n\,-\,1] where *[tex \Large n] is any integer. The next consecutive integer is 2 more: *[tex \Large 2n\,+\,1]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (2n\,-\,1)(2n\,+\,1)\ =\ 5(2n\,-\,1\ +\ 2n\,+\,1)\ +\ 143]


Solve for *[tex \Large n], then calculate *[tex \Large 2n\,-\,1] and *[tex \Large 2n\,+\,1]


Hint: The equation is a quadratic.  There are two solutions.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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