Question 108126
 x+3_>4 and -4x<20
First equation
{{{x+3>=4}}}
{{{x+3-3>=4-3}}} Subtract 3 from both sides.
{{{x>=1}}}
Second equation
{{{-4x<20}}}
{{{-4x/(-4)>20/(-4)}}}Divide both sides by (-4), change direction of inequality. 
{{{x>-5}}}
Since you must satisfy both conditions
{{{x>=1}}} and {{{x>-5}}}, then the solution is
{{{x>=1}}}